Show each step of your work and fully simplify each expression.
Turn in your answers in class on a physical piece of paper.
Staple multiple sheets together.
Feel free to use Desmos for graphing.
Answer the following:
Suppose your friend was given a function \[f(x) = x^2 - 3\] and they are asked to find $f(x + h) - f(x)$. Your friend ends up writing \[f(x + h) - f(x) = x^2 - 3 + h - x^2 - 3\] Identify the two mistakes that were made.
Find the domain of the following functions:
$f(x) = \dfrac{1}{\sqrt{2x - 1}}$
$f(x) = \dfrac{1}{x\sqrt{2x - 4}}$ Hint Use the zero product property when setting denominator to zero.
$g(x) = \sqrt{x-2} - \dfrac{2x}{\sqrt{-x + 3}}$
Let \[f(x) = \begin{cases} 3x + 2 & x \geq 2 \\ x^2 - x & x < 2\end{cases}\] Evaluate the following:
$f(0)$
$f(1)$
$f(2)$
$f(3)$
$f(4)$
Let \[f(x) = \begin{cases}-1 & x < -1 \\ x & -1 \leq x \leq 1 \\ -1 & x > 1\end{cases}\] Evaluate the following:
$f(-2)$
$f(-1)$
$f(0)$
$f(0.99)$
$f(1)$
$f(2)$
Sketch a graph on the coordinate plane for the following functions using the table. Feel free to verify your graphs with Desmos.
$f(x) = 1-x^2$
$g(x) = x^3 + 1$
$f(x) = \begin{cases} -x - 1 & x \leq 1 \\ x + 1 & x > 1\end{cases}$
$f(x) = \begin{cases} x & x > 1 \\ x^2 - 1 & x \leq -1\end{cases}$
$f(x) = \begin{cases} 1 & x \geq 2 \\ -1 & x < 2 \end{cases}$
$g(x) = \begin{cases} x & x > 0 \\ 1 & x = 0 \\ -2x + 3 & x < 0 \end{cases}$
Draw a curve in the plane that is not the graph of a function.
Is this expression a function? Why or why not?
\[f(x) = \begin{cases}x^2 - 3 & x \geq 0 \\ -x - 4 & x \leq 0\end{cases}\]
Given the two functions $f$ and $g$
What is $f(0)$?
What is $g(3)$?
Solve the equation $f(x) = g(x)$.
Solve the equation $f(x) < g(x)$.
Solve the equation $f(x) \geq g(x)$.
On what intervals is $f(x)$ increasing and decreasing?
On what intervals is $g(x)$ increasing and decreasing?
What is the local maxima of $f(x)$?
Solve the following equations/inequalities with 1.5 methods or using the graph. You can use Desmos (but graph both graphs on the homework you will submit).
$x - 2 = 4 - x$
$x^3 + 3x^2 = -x^2 + 5x$
$x^3 + 3x^2 < -x^2 + 5x$
$16x^3 + 16x^2 = x + 1$
$1 + \sqrt{x} = \sqrt{x^2 + 1}$
Find the increasing/decreasing intervals and all local maxima/minima and the location at which they occur:
What is the average rate of change of $f(x)$ on $(x, x + h)$ defined as?
If a function has negative average rate of change on $(a, b)$, must it be decreasing on $(a, b)$? If not, draw a counterexample.
Find the average rate of change for the following functions between the given values. Fully simplify when necessary.
$f(x) = \sqrt{x}; \qquad (x, x + h)$
Hint Rationalize the numerator.
$f(x) = x^3 - 4x^2; \qquad (0, 10)$
$f(x) = 3x - 2; \qquad (2, 3)$
$f(x) = 1 - 3x^2; \qquad (2, 2 + h)$
$f(x) = \dfrac{1}{x}; \qquad (x, x + h)$
Which transformations should be last?
If I have a base function $f(x)$, explain in English what the following transformations will do to $f(x)$: