Homework 8
Directions:
- Show each step of your work and fully simplify each expression.
- Turn in your answers in class on a physical piece of paper.
- Staple multiple sheets together.
- Feel free to use Desmos for graphing.
Answer the following:
- If I have a polynomial $P(x)$ and I divide it by $x - c$, is the remainder $P(c)$?
- If I have a polynomial $P(x)$ and $P(-222) = 0$, what must be a factor of $P(x)$?
- If I have a polynomial $P(x)$ and $x + 3$ is a factor, is $P(3) = 0$?
- If I divide $x^3 + 3x^2 - 7x + 6$ by $x - 2$, what is the remainder? You can either justify with the Remainder Theorem or long division.
- If \[x^{201} - 2x^{199} + x^{52} - 2x^{32} + 3x + 1\] is divided by $x - 1$, what is the remainder?
- Suppose $P(x) = x^4 - 10x^2 + 9$. We know that $P(3) = 0$. What is the remainder when $P(x)$ is divided by $x - 3$?
- Two polynomials $P$ and $D$ are given. Use long division to divide $P(x)$ by $D(x)$ and express $P$ in the form \[P(x) = D(x)\cdot Q(x) + R(x)\]
- $P(x) = x^4 + 2x^3 - 10x, \qquad D(x) = x - 3$
- $P(x) = 18x^5 - 9x^4 + 3x^2 - 3, \qquad D(x) = 3x^2 - 3x + 1$
- Divide the following polynomials using long division. Write your answer as $P(x) = D(x) \cdot Q(x) + R(x)$.
- $\dfrac{4x^3 + 2x^2 - 2x - 3}{2x + 1}$
- $\dfrac{x^6 + x^4 + x^2 + 1}{x^2 + 1}$
Hint Don't forget a placeholder for the divisor.
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A polynomial $P(x)$ is given, with a few zeros.
Find a complete factorization over $\mathbb{R}$ using the division algorithm.
You must use long division or no credit is received.
- $P(x) = x^3 + 2x^2 - 13x + 10, \qquad x = 1$
- $P(x) = 3x^4 - x^3 - 21x^2 -11x + 6, \qquad x = -1, -2$
- $P(x) = 4x^4 - 4x^3 - 3x^2 + 2x + 1, \qquad x = 1$
- $P(x) = x^4 - 5x^3 + 6x^2 + 4x - 8, \qquad x = 2$
- Find a polynomial of degree 4 with zeroes $-1, 0, 2$ and $\sqrt{2}$.
- Find a polynomial of degree 6 with zeroes $-3, 2$ and $4$.
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What is the definition of an irreducible polynomial?
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Write down the definition of zero from Section 3.2. I will ask you to recall this definition on next week's quiz!
- Suppose $P(x)$ factors into two irreducible quadratics and three linear factors over $\mathbb{R}$. What is the degree of $P(x)$?
- Given a complete factorization over $\mathbb{R}$, how do you find a complete factorization over $\mathbb{C}$?
- State whether each of the following statements are true or false.
- The point of Section 3.3 and Section 3.5 is to describe how polynomials factor.
- Every real number is a complex number.
- In the Real Factorization Theorem, it is possible for a polynomial to factor into only irreducible polynomials.
- The polynomial $P(x) = x^{234} - 4x^{22} - 4$ factors into $234$ linear factors over $\mathbb{C}$.
- Irreducible polynomials always factor into two linear factors over $\mathbb{R}$.
- The polynomial $P(x) = x^2 + 2$ factors into two linear factors over $\mathbb{R}$.
- The polynomial $P(x) = x^3 + x$ has one real zero and two complex zeros.
- Given a polynomial $P(x)$, the complete factorization over $\mathbb{R}$ is always the same as the complete factorization over $\mathbb{C}$.
- A complete factorization over $\mathbb{R}$ always results in linear factors.
- A polynomial of degree $n$ will always have $n$ real zeros.
- A polynomial of degree $n$ will always have $n$ complex zeros.
- Describe a polynomial of degree 5 with 3 linear factors and one irreducible factor.
- Suppose $P(x) = x^3 - x - 6$. Out of the numbers $-2, -1, 0, 1, 2$, which one(s) are zeros of $P(x)$?
- If $P(x)$ is degree two with two complex zeros $x = \dfrac{1 \pm i\sqrt{5}}{3}$, what does the complete factorization over $\mathbb{C}$ look like?
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A polynomial is given, sometimes with a few zeros. Do three things for each one:
① Determine the number of zeros, counting multiplicity.
② Find a complete factorization over $\mathbb{R}$.
③ Find a complete factorization over $\mathbb{C}$.
- $P(x) = 2x^2 - 2x + 3$
- $P(x) = x^3 + 2x^2 + 4x + 8$
- $P(x) = x^3 -7x^2 + 17x - 15 \qquad$ where $P(3) = 0$ (no need to verify).
- $P(x) = x^3 - x - 6 \qquad$ (use the zero from Problem 18).
- $P(x) = x^4 + 8x^2 + 16$
- $P(x) = 2x^6 - 4x^4 + 2x^2$
- $P(x) = 2x^3 - 8x^2 + 9x - 9 \qquad$ where $x = 3$ is a zero.
Hint If you are struggling, see the example we did in class, which has a solution online now!